Jika d memenuhi persamaan ⁴log.⁴logx-⁴log.⁴log.⁴log.⁴log16=2, maka ^16logx sama dengan??? A. 4. B.2. C.1. D. -2. E.-4
Jika d memenuhi persamaan
⁴log.⁴logx-⁴log.⁴log.⁴log.⁴log16 = 2,
Jawab;
⁴log.⁴logx-⁴log.⁴log.⁴log16 = 2
maka ^16logx sama dengan....
Jawab;
⁴log.⁴logx-⁴log.⁴log.⁴log16 = 2
⁴log.⁴logx - ⁴log.⁴log.⁴log4² = 2
⁴log.⁴logx- ⁴log.⁴log2 = 2
⁴log.⁴logx- ⁴log.²^²log2 = 2
⁴log.⁴logx - ⁴log½ = 2
⁴log.⁴logx-²^²log2–¹ = 2
⁴log.⁴logx - (-½) = 2
⁴log.⁴logx + ½ = 2
⁴log.⁴logx = 2 - ½
⁴log.⁴logx = 3/2
⁴log.⁴logx = ⁴log4^3/2
⁴logx = 4^3/2
⁴log.⁴logx- ⁴log.²^²log2 = 2
⁴log.⁴logx - ⁴log½ = 2
⁴log.⁴logx-²^²log2–¹ = 2
⁴log.⁴logx - (-½) = 2
⁴log.⁴logx + ½ = 2
⁴log.⁴logx = 2 - ½
⁴log.⁴logx = 3/2
⁴log.⁴logx = ⁴log4^3/2
⁴logx = 4^3/2
Sehingga dapat kita ketahui :
^16logx= ⁴^²logx= ½.⁴logx
= ½.4^3/2
= ½. (2²)^3/2
= ½. 2³
= ½.8
= 4
= ½.4^3/2
= ½. (2²)^3/2
= ½. 2³
= ½.8
= 4
Jawabannya (A).
Itulah contoh pembahasan tentan materi logaitma, semoga bermanfaat yahh temen-temen, Happy studying..
0 Response to "Jika d memenuhi persamaan ⁴log.⁴logx-⁴log.⁴log.⁴log.⁴log16=2, maka ^16logx sama dengan??? A. 4. B.2. C.1. D. -2. E.-4"
Post a Comment